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▪Softmax算法:逻辑回归的扩展 终于实现了逻辑回归的扩展版本,训练方法采用梯度下降法,这种方法对学习率的要求比较高,不同的学习率可能导致结果大相径庭。见相关图
参考资料:http://deeplearning.stanford.edu/wiki/index.php.........
▪最小生成树---Kruskal算法---挑战程序设计竞赛读书笔记 图和上一篇prim算法一样:http://blog.csdn.net/xiaozhuaixifu/article/details/9864355
测试数据也一样。
这个算法用到并查集来高效的判断顶点u,v是否属于同一个联通分量。
关于并查集:http://blog.csdn.net/xiao.........
▪J2EE struts2 登录验证
1 整体结构纵览
1.1 配置文件
Java Resources/src/struts.xml
WebContent/WEB-INF/web.xml
1.2 java文件
Java Resources/src/lee/LoginAction.java
1.3 jsp文件
WebContent/error.jsp
WebContent/index.jsp
WebContent/welcome.jsp
1.4 jar文件
WebC.........
[1]Softmax算法:逻辑回归的扩展
来源: 互联网 发布时间: 2013-10-26
终于实现了逻辑回归的扩展版本,训练方法采用梯度下降法,这种方法对学习率的要求比较高,不同的学习率可能导致结果大相径庭。见相关图
参考资料:http://deeplearning.stanford.edu/wiki/index.php/Softmax%E5%9B%9E%E5%BD%92
Python代码如下:
import numpy as np import matplotlib.pylab as plt import copy from scipy.linalg import norm from math import pow from scipy.optimize import fminbound,minimize import random def _dot(a, b): mat_dot = np.dot(a, b) return np.exp(mat_dot) def condProb(theta, thetai, xi): numerator = _dot(thetai, xi.transpose()) denominator = _dot(theta, xi.transpose()) denominator = np.sum(denominator, axis=0) p = numerator / denominator return p def costFunc(alfa, *args): i = args[2] original_thetai = args[0] delta_thetai = args[1] x = args[3] y = args[4] lamta = args[5] labels = set(y) thetai = original_thetai thetai[i, :] = thetai[i, :] - alfa * delta_thetai k = 0 sum_log_p = 0.0 for label in labels: index = y == label xi = x[index] p = condProb(original_thetai,thetai[k, :], xi) log_p = np.log10(p) sum_log_p = sum_log_p + log_p.sum() k = k + 1 r = -sum_log_p / x.shape[0]+ (lamta / 2.0) * pow(norm(thetai),2) #print r ,alfa return r class Softmax: def __init__(self, alfa, lamda, feature_num, label_mum, run_times = 500, col = 1e-6): self.alfa = alfa self.lamda = lamda self.feature_num = feature_num self.label_num = label_mum self.run_times = run_times self.col = col self.theta = np.random.random((label_mum, feature_num + 1))+1.0 def oneDimSearch(self, original_thetai,delta_thetai,i,x,y ,lamta): res = minimize(costFunc, 0.0, method = 'Powell', args =(original_thetai,delta_thetai,i,x,y ,lamta)) return res.x def train(self, x, y): tmp = np.ones((x.shape[0], x.shape[1] + 1)) tmp[:,1:tmp.shape[1]] = x x = tmp del tmp labels = set(y) self.errors = [] old_alfa = self.alfa for kk in range(0, self.run_times): i = 0 for label in labels: tmp_theta = copy.deepcopy(self.theta) one = np.zeros(x.shape[0]) index = y == label one[index] = 1.0 thetai = np.array([self.theta[i, :]]) prob = self.condProb(thetai, x) prob = np.array([one - prob]) prob = prob.transpose() delta_thetai = - np.sum(x * prob, axis = 0)/ x.shape[0] + self.lamda * self.theta[i, :] #alfa = self.oneDimSearch(self.theta,delta_thetai,i,x,y ,self.lamda)#一维搜索法寻找最优的学习率,没有实现 self.theta[i,:] = self.theta[i,:] - self.alfa * np.array([delta_thetai]) i = i + 1 self.errors.append(self.performance(tmp_theta)) def performance(self, tmp_theta): return norm(self.theta - tmp_theta) def dot(self, a, b): mat_dot = np.dot(a, b) return np.exp(mat_dot) def condProb(self, thetai, xi): numerator = self.dot(thetai, xi.transpose()) denominator = self.dot(self.theta, xi.transpose()) denominator = np.sum(denominator, axis=0) p = numerator[0] / denominator return p def predict(self, x): tmp = np.ones((x.shape[0], x.shape[1] + 1)) tmp[:,1:tmp.shape[1]] = x x = tmp row = x.shape[0] col = self.theta.shape[0] pre_res = np.zeros((row, col)) for i in range(0, row): xi = x[i, :] for j in range(0, col): thetai = self.theta[j, :] p = self.condProb(np.array([thetai]), np.array([xi])) pre_res[i, j] = p r = [] for i in range(0, row): tmp = [] line = pre_res[i, :] ind = line.argmax() tmp.append(ind) tmp.append(line[ind]) r.append(tmp) return np.array(r) def evaluate(self): pass def samples(sample_num, feature_num, label_num): n = int(sample_num / label_num) x = np.zeros((n*label_num, feature_num)) y = np.zeros(n*label_num, dtype=np.int) for i in range(0, label_num): x[i*n : i*n + n, :] = np.random.random((n, feature_num)) + i y[i*n : i*n + n] = i return [x, y] def save(name, x, y): writer = open(name, 'w') for i in range(0, x.shape[0]): for j in range(0, x.shape[1]): writer.write(str(x[i,j]) + ' ') writer.write(str(y[i])+ '\n') writer.close() def load(name): x = [] y = [] for line in open(name, 'r'): ele = line.split(' ') tmp = [] for i in range(0, len(ele) - 1): tmp.append(float(ele[i])) x.append(tmp) y.append(int(ele[len(ele) - 1])) return [x, y] def plotRes(pre, real, test_x,l): s = set(pre) col = ['r','b','g','y','m'] fig = plt.figure() ax = fig.add_subplot(111) for i in range(0, len(s)): index1 = pre == i index2 = real == i x1 = test_x[index1, :] x2 = test_x[index2, :] ax.scatter(x1[:,0],x1[:,1],color=col[i],marker='v',linewidths=0.5) ax.scatter(x2[:,0],x2[:,1],color=col[i],marker='.',linewidths=12) plt.title('learning rating='+str(l)) plt.legend(('c1:predict','c1:true',\ 'c2:predict','c2:true', 'c3:predict','c3:true', 'c4:predict','c4:true', 'c5:predict','c5:true'), shadow = True, loc = (0.01, 0.4)) plt.show() if __name__ == '__main__': #[x, y] = samples(1000, 2, 5) #save('data.txt', x, y) [x, y] = load('data.txt') index= range(0, len(x)) random.shuffle(index) x = np.array(x) y = np.array(y) x_train = x[index[0:700],:] y_train = y[index[0:700]] softmax = Softmax(0.4, 0.0, 2, 5)#这里讲第二个参数设置为0.0,即不用正则化,因为模型中没有高次项,用正则化反而使效果变差 softmax.train(x_train, y_train) x_test = x[index[700:1000],:] y_test = y[index[700:1000]] r= softmax.predict(x_test) plotRes(r[:,0],y_test,x_test,softmax.alfa) t = r[:,0] != y_test o = np.zeros(len(t)) o[t] = 1 err = sum(o)
作者:zc02051126 发表于2013-8-9 23:35:44 原文链接
阅读:0 评论:0 查看评论
[2]最小生成树---Kruskal算法---挑战程序设计竞赛读书笔记
来源: 互联网 发布时间: 2013-10-26
图和上一篇prim算法一样:http://blog.csdn.net/xiaozhuaixifu/article/details/9864355
测试数据也一样。
这个算法用到并查集来高效的判断顶点u,v是否属于同一个联通分量。
关于并查集:http://blog.csdn.net/xiaozhuaixifu/article/details/9822151
代码:
#include <iostream> #include <cstring> #include <cstdlib> #include <algorithm> #include <fstream> using namespace std; const int max_e=100; const int max_v=100; const int inf=99999; struct edge{ int from,to,weight; } ; edge es[max_e]; bool cmp(const edge &a,const edge &b){ return a.weight<b.weight; } int V,E; //V vertexs,{1,2,3...n}, E edges. // union_set int par[max_v],rank[max_v]; void inin_union_set(int v) { for(int i=1;i<=v;i++){ par[i]=i; rank[i]=0; } } int find(int x){ if(par[x]==x)return x; else return par[x]=find(par[x]); } void union_set(int x,int y){ x=find(x); y=find(y); if(x==y)return ; if(rank[x]<rank[y]){ par[x]=y; } else { par[y]=x; if(rank[x]==rank[y]) rank[x]++; } } int Kruskal() { sort(es,es+E,cmp); inin_union_set(V); int res=0; for(int i=0;i<E;i++) { edge e=es[i]; if( find(e.from)!=find(e.to) ) { union_set(e.from,e.to); res+=e.weight; } } return res; } int main() { ifstream fin; fin.open("input.txt"); while(fin>>V>>E) { for(int i=0;i<E;i++){ fin>>es[i].from>>es[i].to>>es[i].weight; } cout<<Kruskal()<<endl; } return 0; }
作者:xiaozhuaixifu 发表于2013-8-9 21:53:58 原文链接
阅读:19 评论:0 查看评论
[3]J2EE struts2 登录验证
来源: 互联网 发布时间: 2013-10-26
1 整体结构纵览
1.1 配置文件
Java Resources/src/struts.xml
WebContent/WEB-INF/web.xml
1.2 java文件
Java Resources/src/lee/LoginAction.java
1.3 jsp文件
WebContent/error.jsp
WebContent/index.jsp
WebContent/welcome.jsp
1.4 jar文件
WebContent/WEB-INF/lib/
包括
commons-fileupload.jar
commons-logging-api.jar
freemaker.jar
ognl.jar
struts-core.jar
xwork.jar
1.5 国际化资源文件
WebContent/WEB-INF/classes/lee/messageResource_zh_CN.properties
WebContent/WEB-INF/classed/lee/messageResource.properties
注: 国际化步骤
编写资源文件
在struts.xml文件中声明以便加载资源文件
使用bean标签显示国际化信息
2 具体实现
2.1 配置文件实现
web.xml
<?xml version="1.0" encoding="gbk"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
struts.xml
<?xml version="1.0" encoding="gbk"?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<!-- 指定Struts 2配置文件的根元素 -->
<struts>
<!-- 指定全局国际化资源文件base名 -->
<constant name="struts.custom.i18n.resources" value="messageResource" />
<!-- 指定国际化编码所使用的字符集 -->
<constant name="struts.i18n.encoding" value="GBK" />
<!-- 所有的Action定义都应该放在package下 -->
<package name="lee" extends="struts-default">
<action name="login" class="lee.LoginAction">
<!-- 定义三个逻辑视图和物理资源之间的映射 -->
<result name="input">/login.jsp</result>
<result name="error">/error.jsp</result>
<result name="success">/welcome.jsp</result>
</action>
</package>
</struts>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<!-- 指定Struts 2配置文件的根元素 -->
<struts>
<!-- 指定全局国际化资源文件base名 -->
<constant name="struts.custom.i18n.resources" value="messageResource" />
<!-- 指定国际化编码所使用的字符集 -->
<constant name="struts.i18n.encoding" value="GBK" />
<!-- 所有的Action定义都应该放在package下 -->
<package name="lee" extends="struts-default">
<action name="login" class="lee.LoginAction">
<!-- 定义三个逻辑视图和物理资源之间的映射 -->
<result name="input">/login.jsp</result>
<result name="error">/error.jsp</result>
<result name="success">/welcome.jsp</result>
</action>
</package>
</struts>
2.2 java文件实现
LoginAction.java文件
package lee;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ActionContext;
/**
* Description:
* <br/>Copyright (C), 2008-2010, Yeeku.H.Lee
* <br/>This program is protected by copyright laws.
* <br/>Program Name:
* <br/>Date:
* @author Yeeku.H.Lee kongyeeku@163.com
* @version 1.0
*/
//Struts2的Action继承了ActionSupport
public class LoginAction extends ActionSupport
{
//定义封装请求参数的username和password属性
private String username;
private String password;
public String getUsername()
{
return username;
}
public void setUsername(String username)
{
this.username = username;
}
public String getPassword()
{
return password;
}
public void setPassword(String password
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ActionContext;
/**
* Description:
* <br/>Copyright (C), 2008-2010, Yeeku.H.Lee
* <br/>This program is protected by copyright laws.
* <br/>Program Name:
* <br/>Date:
* @author Yeeku.H.Lee kongyeeku@163.com
* @version 1.0
*/
//Struts2的Action继承了ActionSupport
public class LoginAction extends ActionSupport
{
//定义封装请求参数的username和password属性
private String username;
private String password;
public String getUsername()
{
return username;
}
public void setUsername(String username)
{
this.username = username;
}
public String getPassword()
{
return password;
}
public void setPassword(String password
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