单链表的逆序输出分为两种情况，一种是只逆序输出，实际上不逆序；另一种是把链表逆序。本文就分别实例讲述一下两种方法。具体如下：
1.逆序输出
实例代码如下：
#include
#include
#include
using namespace std;
typedef struct node{
int data;
node * next;
}node;
//尾部添加
node * add(int n, node * head){
node * t = new node;
t->data = n;
t->next = NULL;
if (head == NULL){
head = t;
}
else if (head->next == NULL){
head->next = t;
}
else{
node * p = head->next;
while (p->next != NULL){
p = p->next;
}
p->next = t;
}
return head;
}
//顺序输出
void print(node * head){
node * p = head;
while (p != NULL){
cout data next;
}
cout next);
cout data data);
head = head->next;
}
while (!s.empty()){
cout next == NULL){
head->next = t;
}
else{
node * p = head->next;
while (p->next != NULL){
p = p->next;
}
p->next = t;
}
return head;
}
//循环
node * reverse(node * head){
if (head == NULL || head->next == NULL){
return head;
}
node * p1 = head;
node * p2 = head->next;
node * p3 = NULL;
head->next = NULL;
while (p2 != NULL){
p3 = p2;
p2 = p2->next;
p3->next = p1;
p1 = p3;
}
head = p1;
return head;
}
void print(node * head){
node * p = head;
while (p != NULL){
cout data next;
}
cout next == NULL){
return p;
}
node * newHead = reverse2(p->next);
p->next->next = p;
p->next = NULL;
return newHead;
}
int main(){
node * head = NULL;
for (int i = 1; i