下面是我的程序：
//Pump.java
package bumf;

import java.applet.Applet;
import java.applet.AppletContext;

public class Pump extends Applet
{
public static Pump selRef = null;
private LookFor1 tmp;
public void init()
{
selRef = this;
tmp = new LookFor1();
tmp.setBounds(0,0,800,600);
tmp.show();

}
public void start()
{
}
}
//LookFor1.java
package bumf;

import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.net.*;
import java.beans.*;

/**
*@author:GuoCX
*@descriptor:公文关键词搜索，排序，时间和类别的调整
*Time:2000:6:21
*/

public class LookFor1 extends Frame
{
private Pump m_Ref = null;
private Panel m_panel = new Panel();
public LookFor1()
{
super("公文管理器");

setLayout(new BorderLayout());
add(m_panel,"Center");
                addWindowListener(new WindowAdapter()
{
public void windowClosing (WindowEvent event)
{
dispose();
                                System.exit(0);
}
});
m_Ref = Pump.selRef;
addMouseListener(new MouseAdapter(){
                        public void mouseClicked(MouseEvent e)
                        {
try{
m_Ref.getAppletContext().showDocument(new URL("http://10.109.41.6"),"_blank");
                                                }
                                                catch(java.net.MalformedURLException ex)
                                                {
                                                System.out.println("java.net.Malf:" + ex.getMessage());
                                                }
}
});

}
}
//测试.html


运行测试.html,弹出一个Frame,点击无反应(我原想点击Frame时测试.html该显示http://10.109.41.6的内容).运行在IE5+WIN2000环境下.
另外,象这种Applet该怎么调试?还有,我现在的工作是JSP,很简单,但以后怎么在工作中深入应用java呢?谢谢!

在 Applet 中很难访问不是源服务器的其他URL地址的内容的，是由浏览器的安全模型所限制的。