当前位置: 编程技术>python
用python实现的可以拷贝或剪切一个文件列表中的所有文件
来源: 互联网 发布时间:2014-09-04
本文导语: 代码如下:# coding:utf-8 import os import sys def cut_and_paste_file(source, destination): ''' source: file path 中文 destination: directory path ''' def format_path(path): if not os.path.isabs(path): path = os.p...
代码如下:
# coding:utf-8
import os
import sys
def cut_and_paste_file(source, destination):
'''
source: file path 中文
destination: directory path
'''
def format_path(path):
if not os.path.isabs(path):
path = os.path.join(os.getcwd(), path)
return path
def mk_dir(path):
if not os.path.exists(os.path.dirname(path)):
mkdir_cmd = 'mkdir "%s"' % os.path.dirname(path)
print os.popen(mkdir_cmd).read()
destination = os.path.join(format_path(destination), source)
source = format_path(source)
mk_dir(source)
mk_dir(destination)
copy_cmd = 'copy /Y "%s" "%s"' % (source, destination)
print 'copy_cmd:%s' % copy_cmd
print os.popen(copy_cmd).read()
del_cmd = 'del "%s" /Q' % source
print 'del_cmd:%s' % del_cmd
print os.popen(del_cmd).read()
if __name__ == '__main__':
if len(sys.argv) != 2:
print 'params must be 1,the params is the file of contain the list of cutAndPastFile List'
exit(0)
file_name = sys.argv[1]
f = open(file_name, 'r')
lst_file = f.readlines()
f.close()
output_path = 'backup_del'
for filename in lst_file:
filename = filename.replace('n', '')
if filename != '':
cut_and_paste_file(filename, output_path)
传一个文件给该py文件即可,例如,文件名为:del_file.txt
group1_inputsubgroup1355657_XSL_Transformations_(XSLT)_Version_2.0.doc
group1_inputsubgroup6377-6700-001 REV B .doc
group3_inputsubgroup42CGP_Manual_5_0.doc