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SQL 比较一个集合是否在另一个集合里存在的方法分享
来源: 互联网 发布时间:2014-10-04
本文导语: 代码如下: DECLARE @c INT DECLARE @c2 INT SELECT @c = COUNT(1) FROM dbo.SplitToTable('1|2|3|4', '|') SELECT @c2=COUNT(1) FROM dbo.SplitToTable('1|2|3|4', '|') a INNER JOIN dbo.SplitToTable('1|2|3|', '|') b ON a.value = b.value IF @c = @c2 SELECT 'ok' ELSE SELECT 'no' SplitToTable这个函数...
代码如下:
DECLARE @c INT
DECLARE @c2 INT
SELECT @c = COUNT(1)
FROM dbo.SplitToTable('1|2|3|4', '|')
SELECT @c2=COUNT(1)
FROM dbo.SplitToTable('1|2|3|4', '|') a
INNER JOIN dbo.SplitToTable('1|2|3|', '|') b ON a.value = b.value
IF @c = @c2
SELECT 'ok'
ELSE
SELECT 'no'
SplitToTable这个函数如下:
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
go
ALTER FUNCTION [dbo].[SplitToTable]
(
@SplitString NVARCHAR(MAX) ,
@Separator NVARCHAR(10) = ' '
)
RETURNS @SplitStringsTable TABLE
(
[id] INT IDENTITY(1, 1) ,
[value] NVARCHAR(MAX)
)
AS
BEGIN
DECLARE @CurrentIndex INT ;
DECLARE @NextIndex INT ;
DECLARE @ReturnText NVARCHAR(MAX) ;
SELECT @CurrentIndex = 1 ;
WHILE ( @CurrentIndex