15位身份证升18位身份证的Oracle函数：
CREATEORREPLACEFUNCTION FUNC_AAC00215_18 (prm_aac002 varchar2)
return varchar2 is
ll_i number(4) := 18;
ll_row number(5) := 0;
var_aac002 varchar2(18);
ll_sfz18 number(3);
ll_sfz varchar2(3);
var_sfz18 varchar(18);
var_date varchar(10);
dat_date date;
ll_num number(2);
s_sfz varchar2(15);
s_sss varchar2(20):='X';
v_newaac002 varchar(18);
n_length number(2);
V_CHAR varchar2(15);
s_date varchar2(15);
begin
if prm_aac002 isnullthen
return'';
end if;
if length(prm_aac002) 15 and length(prm_aac002) 18 then
return'';
end if;
if length(prm_aac002) = 18 then
n_length := length(prm_aac002);
FOR n_i IN 1 .. n_length LOOP
V_CHAR := SUBSTR(prm_aac002, n_i, 1);
IF V_CHAR IN ('0', '1', '2', '3', '4', '5', '6', '7', '8', '9') AND N_I20 or substr(prm_aac002,7, 2) = 2 loop
begin
select to_number(substr(prm_aac002, 19 - n_length, 1))
into ll_num
from dual;
exception
when others then
return'';
end;
ll_row := ll_row + mod(power(2, (n_length - 1)), 11) *
to_number(substr(prm_aac002, 19 - n_length, 1));
n_length := n_length - 1;
end loop;
ll_sfz18 := mod(ll_row, 11);
select decode(to_char(ll_sfz18),'0','1','1','0','2','X','3','9','4','8','5','7','6','6','7','5','8','4','9','3','10','2')
into ll_sfz
from dual;
if ll_sfz substr(prm_aac002,18, 1) then
return'尾数不对！应为'||ll_sfz;
end if;
RETURN v_newaac002;
end if;
if prm_aac002 = '111111111111111111'then
return'';
end if;
if s_sfz 'X'then
s_sss := s_sfz;
else
s_sss := prm_aac002;
end if;
if length(prm_aac002)=15 then
var_date := '19' || substr(s_sss, 7, 6);
begin
select to_date(var_date, 'yyyymmdd') into dat_date from dual;
exception
when others then
return'';
end;
var_aac002 := substr(s_sss, 0, 6) || '19' ||
substr(s_sss, 7, 9);
while ll_i >= 2 loop
begin
select to_number(substr(var_aac002, 19 - ll_i, 1))
into ll_num
from dual;
exception
when others then
return'';
end;
ll_row := ll_row + mod(power(2, (ll_i - 1)), 11) *
to_number(substr(var_aac002, 19 - ll_i, 1));
ll_i := ll_i - 1;
end loop;
ll_sfz18 := mod(ll_row, 11);
select decode(to_char(ll_sfz18),'0','1','1','0','2','X','3','9','4','8','5','7','6','6','7','5','8','4','9','3','10','2')
into ll_sfz
from dual;
var_sfz18 := var_aac002 || ll_sfz;
return var_sfz18;
end if;
end func_aac00215_18;
/
show errors;
使用如下:
SELECT func_aac00215_18('371102841104258') FROM dual;
