1、 本想使用dbms_advisor做一个sql access advisor测试，不料却遇ORA-13600 QSM-00794报错，如下：
SQL> DECLARE
2 task_name VARCHAR2(200);
3 BEGIN
4 task_name := 'My_Task';
5 DBMS_ADVISOR.QUICK_TUNE(DBMS_ADVISOR.SQLACCESS_ADVISOR,'My_Task',
6 'select * from system.litest_8 where object_id=20');
7 END;
8 /
DECLARE
*
ERROR at line 1:
ORA-13600: error encountered in Advisor
QSM-00794: the statement can not be stored due to a violation of the invalid
table reference filter
ORA-06512: at "SYS.PRVT_ACCESS_ADVISOR", line 1809
ORA-06512: at "SYS.WRI$_ADV_SQLACCESS_ADV", line 180
ORA-06512: at "SYS.PRVT_ADVISOR", line 3678
ORA-06512: at "SYS.DBMS_ADVISOR", line 711
ORA-06512: at line 5
注意上面标红色部分，表的schema为system
2、上metalink上查原因，发现有文章ID：403358.1中做了详细原因描述
SQL Access Advisor maintains an internal list of non-tunable tables regardless of the contents of
the INVALID_TABLE_LIST parameter.
No table that is owned by SYS, SYSTEM or any other pre-defined Oracle schema can be tuned.
看来原因是因为dbms_advisor.quick_tune不支持为SYS和SYSTEM两个用户的表的顾问功能了。
3、将测试的表改到其他用户下试试
3.1 在litest这个用户下创建表
SQL> create table litest.litest_8 asselect * from system.litest_8
3.2 重新用DBMS_ADVISOR.QUICK_TUNE使用sql access advisor功能
SQL> DECLARE
2 task_name VARCHAR2(200);
3 BEGIN
4 task_name := 'My_Task';
5 DBMS_ADVISOR.QUICK_TUNE(DBMS_ADVISOR.SQLACCESS_ADVISOR,'My_Task',
6 'select * from litest.litest_8 where object_id=20');
7 END;
8 /
PL/SQL procedure successfully completed.
注意上面标绿色部分，更换成了litest（非SYS或SYSTEM用户了）
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