我看了，TomCat的源码根本就不是这个.class的源文件！
因为页面上明明显示的是Name:  Value:
而.java中却是Cookie Name:   Cookie Value:
如果谁能贴一份标准的源文件出来，我给50分

怪了，CookieExample.class和CookieExample.java不是都在这个目录吗：

webappsexamplesWEB-INFclasses

// 
// SourceAgain (TM) v1.10 (Core Java 1.2 Trial)
// (C) 1998 Ahpah Software Inc
// Please visit our website at http://www.ahpah.com for purchasing information.
// 

import java.io.IOException;
import java.io.PrintWriter;
import java.util.ResourceBundle;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.Cookie;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class CookieExample extends HttpServlet {

    ResourceBundle rb = ResourceBundle.getBundle( "LocalStrings" );

    // Please visit http://www.sourceagain.com for product information.

    public void doGet(HttpServletRequest request, HttpServletResponse response)
        throws IOException, ServletException
    {
        PrintWriter out;
        String title;
        Cookie[] cookies;
        Object cookie;
        String String9;

        ((ServletResponse) response).setContentType( "text/html" );
        out = ((ServletResponse) response).getWriter();
        out.println( "" );
        out.println( "" );
        out.println( "" );
        title = rb.getString( "cookies.title" );
        out.println( "" + title + "" );
        out.println( "" );
        out.println( "" );
        out.println( "" );
        out.println( "" );
        out.println( "" );
        out.println( "" );
        out.println( "" + title + "" );
        cookies = request.getCookies();
        if( cookies.length > 0 )
        {
            int i;

            out.println( (String.valueOf( rb.getString( "cookies.cookies" ) )) + "
" );
            for( i = 0; i 

    

 

Apache Tomcat 4.0如何把源文件生成servlet的class文件?