在JSP中
=====================================================
String myUrl=request.getRequestURI();
URL url=new URL(/tech-qa-java/myUrl/index.html);
String myPath=url.getPath();
===============================================
我这样写是错误的?
出错信息:
========================================================
java.net.MalformedURLException: no protocol: /mail/modules/mailproject/maillist.jsp
at java.net.URL.(URL.java:473)
at java.net.URL.(URL.java:376)
at java.net.URL.(URL.java:330)
at modules.mailproject._0002fmodules_0002fmailproject_0002fmaillist_0002ejspmaillist_jsp_0._jspService(_0002fmodules_0002fmailproject_0002fmaillist_0002ejspmaillist_jsp_0.java:105)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:119)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at org.apache.jasper.servlet.JspServlet$JspCountedServlet.service(JspServlet.java:130)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at org.apache.jasper.servlet.JspServlet$JspServletWrapper.service(JspServlet.java:282)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:429)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:500)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at org.apache.tomcat.core.ServletWrapper.doService(ServletWrapper.java:405)
at org.apache.tomcat.core.Handler.service(Handler.java:287)
at org.apache.tomcat.core.ServletWrapper.service(ServletWrapper.java:372)
at org.apache.tomcat.core.ContextManager.internalService(ContextManager.java:812)
at org.apache.tomcat.core.ContextManager.service(ContextManager.java:758)
at org.apache.tomcat.service.http.HttpConnectionHandler.processConnection(HttpConnectionHandler.java:213)
at org.apache.tomcat.service.TcpWorkerThread.runIt(PoolTcpEndpoint.java:416)
at org.apache.tomcat.util.ThreadPool$ControlRunnable.run(ThreadPool.java:501)
at java.lang.Thread.run(Thread.java:484)

==================================================================

加一个处理异常过程:
try{
    String myUrl=request.getRequestURI();
    URL url=new URL(/tech-qa-java/myUrl/index.html);
    String myPath=url.getPath();
}
catch(MalformedURLException e){}

myUrl的型式应该是http://www.csdn.net/expert

myUrl 应该写全 如  http://java.sun.com/index.html
 

同意楼上，给你一个方法，用它来转化
如果用url调硬盘上的一个文件也需要用file://...
   public static final URL createURL(/tech-qa-java/String fileName/index.html) throws Exception
   {
      URL url = null;
      try
      {
         url = new URL(/tech-qa-java/fileName/index.html);
      }
      catch (MalformedURLException ex)
      {
         File f = new File(fileName);
         try
         {
            String path = f.getAbsolutePath();
            String fs = System.getProperty("file.separator");
            if (fs.length() == 1)
            {
               char sep = fs.charAt(0);
               if (sep != '/')
                  path = path.replace(sep, '/');
               if (path.charAt(0) != '/')
                  path = '/' + path;
            }
            path = "file://" + path;
            url = new URL(/tech-qa-java/path/index.html);
         }
         catch (MalformedURLException e)
         {
            System.out.println("Cannot create url for: " + fileName);
            throw new Exception(e.getMessage());
         }
      }
      return url;
   }

myUrl="http://" + myUrl