逻辑上，thread创建成功后，会拷贝原始thread的堆栈信息吗？

ThreadA -+- ThreadA
         |
         |(pthread_create)
         |
         +- ThreadA1

ThreadA1会具有ThreadA的堆栈信息吗？

从下面的例子来看，答案似乎是不。
/*
 * Complier & OS
 *     gcc on SLES 9.3
*/
#include 
#include 
#include 
#include 

#define TH_COUNT 10
//#define pthread_yield()       sleep(1)

int exit_flag = 0;
int indicator = 0;
pthread_mutex_t exit_lock = PTHREAD_MUTEX_INITIALIZER;
pthread_mutex_t print_lock = PTHREAD_MUTEX_INITIALIZER;
pthread_mutex_t indicator_lock = PTHREAD_MUTEX_INITIALIZER;

void printf_r(const char *fmt, ...)
{
    va_list arg_ptr;
    va_start(arg_ptr, fmt);
    pthread_mutex_lock(&print_lock);
    vprintf(fmt, arg_ptr);
    pthread_mutex_unlock(&print_lock);
}

void *th_main(void *arg)
{
        int cont = 0;
        while( cont == 0 )
        {
                pthread_mutex_lock(&indicator_lock);
                cont = indicator;
                pthread_mutex_unlock(&indicator_lock);
                pthread_yield();
        }
        pthread_mutex_lock(&exit_lock);
        exit_flag++;
        pthread_mutex_unlock(&exit_lock);

        printf_r( "arg=%p,*arg=%dn", arg, *((int*)arg) );

        pthread_mutex_lock(&exit_lock);
        exit_flag--;
        pthread_mutex_unlock(&exit_lock);

        return NULL;
}

int run(void)
{
        int i;
        pthread_t th_list[TH_COUNT];
        int value = 1024;
//      int *arg=(int*)malloc(sizeof(int));
        int *arg=NULL;

//      *arg=value;
        arg=&value;

        for( i = 0; i