06/01/11 09:12:08.898 905684484                 
 06/01/11 09:12:10.185 192686122                
 06/01/11 09:12:11.562 569181101                 
 06/01/11 09:12:12.845 852108470                 
 06/01/11 09:12:14.232 239007199                
 06/01/11 09:12:15.547 553735667                 
 06/01/11 09:12:17.56 063616235        
 06/01/11 09:12:18.371 379715781                 
 06/01/11 09:12:19.686 693371008                
 06/01/11 09:12:20.992 999217254                
 06/01/11 09:12:22.307 326243885                 
 06/01/11 09:12:23.612 618656099                 
 06/01/11 09:12:24.922 928787608                  
 06/01/11 09:12:26.214 221596112                  
 06/01/11 09:12:27.537 545335218                  
 06/01/11 09:12:29.121 128158169                
 06/01/11 09:12:30.425 432466015             
 06/01/11 09:12:31.773 781991615                
 06/01/11 09:12:33.70 078175055                
 06/01/11 09:12:34.413 425290525                  
 06/01/11 09:12:35.737 744333151

上面的记录是我打印的时间分别是日期 小时 分钟 秒 毫秒 纳秒

倒数第二列毫秒我是用最后一列纳秒除以1000000，

printf "%s `date +%D %H:%M:%S.``expr `date +%N` / 1000000`">>"$CURDIR/$1_record_$$.txt"|top -b -n 1|grep "$pid"|grep "$1"|grep -v 'grep'>>"$CURDIR/$1_record_$$.txt"


命令就是expr `date +%N` / 1000000。但是现在遇到一个问题 获取的纳秒最前面存在0的情况，比如说078175055，这个数除过以后就变成78了，我现在想保留前面的0变成078。不知道该怎么处理 请高手指点一二 ，不胜感激

printf "%03d" 78