当前位置: 技术问答>linux和unix
大家帮我看个unix shell问题，我是菜鸟！
来源: 互联网 发布时间：2015-08-03
本文导语: #!/bin/sh if [ $# -ne 1 ] then echo "Usage: `basename $0` [DATE(YYYYMM)]" echo "Example: `basename $0` 200201" echo "" exit 0 fi EXC=$1 if [ -f ./jsqd_13697797855_${EXC}.dat ] then ...
#!/bin/sh
if [ $# -ne 1 ]
then
echo "Usage: `basename $0` [DATE(YYYYMM)]"
echo "Example: `basename $0` 200201"
echo ""
exit 0
fi
EXC=$1
if [ -f ./jsqd_13697797855_${EXC}.dat ]
then
echo "exist jsqd_13697797855_${EXC}.dat, delete it first."
exit
fi
zcat /home/js/jdata/qds/wjjsh/${EXC}/nor_file/ZH*.dat.Z | awk '{
zj = substr($0,1,20);
bj = substr($0,21,20);
rqsj = substr($0,57,14);
thsc = substr($0,71,6);
jfsc = substr($0,77,6);
if (zj~/^0756/) {
if (bj~/^13697797855/ )
printf "%-20s:%-20s:%-8s:%-6s:%-6s:%-6sn",substr(zj,5,7),substr(bj,1,20),substr(rqsj,1,8),substr(rqsj,9,6),thsc,jfsc;
}
else if (substr(zj,1,1)!='1' && substr(zj,1,1)!='0') {
if (bj~/^13697797855/ )
printf "%-20s:%-20s:%-8s:%-6s:%-6s:%-6sn",substr(zj,1,7),substr(bj,1,20),substr(rqsj,1,8),substr(rqsj,9,6),thsc,jfsc;
}
}' > ./jsqd_13697797855_${EXC}.dat
fi
echo "formatting wjjs qd,Please wait ..."
Wc -l ./jsqd_13697797855_${EXC}.dat
echo "format done!"
程序一运行，老提示：
format_13697797855.sh: line 34: syntax error near unexpected token `fi'
format_13697797855.sh: line 34: `fi'
到底是那里问题？
if [ $# -ne 1 ]
then
echo "Usage: `basename $0` [DATE(YYYYMM)]"
echo "Example: `basename $0` 200201"
echo ""
exit 0
fi
EXC=$1
if [ -f ./jsqd_13697797855_${EXC}.dat ]
then
echo "exist jsqd_13697797855_${EXC}.dat, delete it first."
exit
fi
zcat /home/js/jdata/qds/wjjsh/${EXC}/nor_file/ZH*.dat.Z | awk '{
zj = substr($0,1,20);
bj = substr($0,21,20);
rqsj = substr($0,57,14);
thsc = substr($0,71,6);
jfsc = substr($0,77,6);
if (zj~/^0756/) {
if (bj~/^13697797855/ )
printf "%-20s:%-20s:%-8s:%-6s:%-6s:%-6sn",substr(zj,5,7),substr(bj,1,20),substr(rqsj,1,8),substr(rqsj,9,6),thsc,jfsc;
}
else if (substr(zj,1,1)!='1' && substr(zj,1,1)!='0') {
if (bj~/^13697797855/ )
printf "%-20s:%-20s:%-8s:%-6s:%-6s:%-6sn",substr(zj,1,7),substr(bj,1,20),substr(rqsj,1,8),substr(rqsj,9,6),thsc,jfsc;
}
}' > ./jsqd_13697797855_${EXC}.dat
fi
echo "formatting wjjs qd,Please wait ..."
Wc -l ./jsqd_13697797855_${EXC}.dat
echo "format done!"
程序一运行，老提示：
format_13697797855.sh: line 34: syntax error near unexpected token `fi'
format_13697797855.sh: line 34: `fi'
到底是那里问题？
|
嘿嘿，再来一遍：我认为是你的嵌套的if没有then并且fi不匹配造成的。
|
sorry，不够仔细
您可能感兴趣的文章:
本站(WWW.)旨在分享和传播互联网科技相关的资讯和技术，将尽最大努力为读者提供更好的信息聚合和浏览方式。
本站(WWW.)站内文章除注明原创外，均为转载、整理或搜集自网络。欢迎任何形式的转载，转载请注明出处。
本站(WWW.)站内文章除注明原创外，均为转载、整理或搜集自网络。欢迎任何形式的转载，转载请注明出处。