想写一个shell，根据查询出的shmid 来杀掉相应的进程
[root@Sender2 ~]# ipcs -m

------ Shared Memory Segments --------
key        shmid      owner      perms      bytes      nattch     status      
0x010320fc 393216     root       666        2588160    2                       
0x01032393 425985     root       666        2588160    2                       
0x000320fc 458754     root       666        35716608   2                       
0x00032393 491523     root       666        35716608   2                       
0x650320fc 524292     root       666        67292160   2                       
0x65032393 557061     root       666        67292160   2                       
0x660320fc 589830     root       666        32093184   2                       
0x66032393 622599     root       666        32093184   2                       
0x670320fc 655368     root       666        7246848    2                       
0x67032393 688137     root       666        7246848    2                       
0x680320fc 720906     root       666        517632     2                       
0x68032393 753675     root       666        517632     2                       
0x690320fc 786444     root       666        8282112    2                       
0x69032393 819213     root       666        8282112    2  

[root@Sender2 ~]#ipcrm shm 392316

ipcrm shm 命令只能一条一条的删，而且每次启动后，这些shmid还会变，有能帮我的么？

[User:root Time:20:23:11 Path:/home/liangdong/shell]$ cat test.sh 

#!/bin/sh 



function ipc_remove() {

        row=0;

        ipcs -$1 | grep -v ^$ | while read line; do 

                if [ "$row" -ge "2" ];then

                        echo $line;

                        shmid=`echo $line | awk '{print $2}'`;

                        if [ "$shmid" -ne "0" ];then

                                ipcrm -$1 $shmid

                        fi

                fi

                let row=$row+1

        done

}



ipc_remove "m";

ipc_remove "s";

ipc_remove "q";

谨慎使用。

试试
ipcs -m | awk '$1~/0x/ {print "ipcrm -M", $1}' | sh